They want to make a profit of $3,000.
Their income is $1.25 per subscription. Then, the total income is 1.25x, being x the number of subscriptions.
Their expenses are fixed (that is, they do not depend on the number of subscriptions) and are $100 and $150, a total of $250.
Then, we can write the equation for the profit P in function of the number of subscriptions as:
![P=1.25x-250](https://img.qammunity.org/2023/formulas/mathematics/college/f0zaxgzvbuuak0xh03mbhci46mr82ciuye.png)
If profit needs to be larger than $3000, we can write:
![\begin{gathered} P>3000 \\ 1.25x-250>3000 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3y5vqs1sdzl9qhtelcdg75fzsq5ojx5nb8.png)
And solve:
![\begin{gathered} 1.25x-250>3000 \\ 1.25x>3000+250 \\ 1.25x>3250 \\ x>(3250)/(1.25) \\ x>2600 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9vkw9jssyq8lupmx836sn04owcuqsytq2q.png)
They need at least 2600 subscriptions to make $3000 in proft.