1 Answer

Stefan Feuerhahn · Answer 1 · 2023-02-28T11:22:40+0000

We must compute the partial sum of a geometric series with:

$\begin{gathered} a_1=4, \\ a_n=128, \\ r=2. \end{gathered}$

The formula for the partial sum is:

$S_n=(a_1-a_n\cdot r)/(1-r)\text{.}$

Replacing the values of the problem in the formula above, we get:

$S_n=(4-128\cdot2)/(1-2)=(4-256)/(-1)=(-252)/(-1)=252.$

Answer

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