Question

Is it possible to operate two 1250 W hair dryers on a 120 V circuit without blowing a 20 amp fuse?

Answer 1

Given:

The power of each hair dryer is,

`P=1250\text{ W}`

The potential across the circuit is,

`V=120\text{ V}`

The fuse has current

`i=20\text{ A}`

To find:

Is it possible to use that fuse or not

Step-by-step explanation:

The power for two heaters is,

`\begin{gathered} P^(\prime)=2P \\ =2*1250 \\ =2500\text{ W} \end{gathered}`

The current for this power is,

`\begin{gathered} I=(P^(\prime))/(V) \\ =(2500)/(120) \\ =20.8\text{ A} \end{gathered}`

Here, we see the current for the dryers is greater than the fuse's current.

Hence, it is not possible to use the given fuse.