Given jack is 3 times as old as lacy.
Let the age of the lacy be x.
Then, the age of the jack is 3x.
After 8 years from now, the sum of their ages will be 64.
![\begin{gathered} (x+3x)+16=64 \\ 4x=64-16 \\ 4x=48 \\ x=(48)/(4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/akh15aemydh6axh6fnsd7nz9k3iyyvkffw.png)
Thus, the value of x will be
![x=12](https://img.qammunity.org/2023/formulas/mathematics/college/9hdf6vcfheavwnbirgtm6p3tt50dvyuld5.png)
Therefore, the age of the lacy is 12 and the age of the jack is
![12*3=36](https://img.qammunity.org/2023/formulas/mathematics/college/63kmnfdtuau1spxqvjy1l7isjb97hzho44.png)
Thus, Jack is 36 years old while lacy is 12 years old.