Given:
The table shows the number of hours of television watched by 129 students per week.
To construct and label a frequency histogram of the data:
Step-by-step explanation:
Since the given class intervals are in the discontinuous form.
In a histogram, the bars should be continuously placed without any gap. Hence we should make the class intervals continuous.
So, let us find the adjustment factor.
![\begin{gathered} Adjustment\text{ }Factor=(1)/(2)\lbrack lower\text{ }limit\text{ of the class interval}-\text{upper limit of the preceding class interval\rbrack} \\ =(1)/(2)\lbrack2-1\rbrack \\ =(1)/(2) \\ =0.5 \end{gathered}]()
So, the table becomes,
The histogram graph is,