Evaluate 16 S (x-4) dx 16 (vx – 4) dx = (Type an exact answer in simplified form.) 9

asked Nov 10, 2023 148k views

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Solution:

$\int ^(16)_9(\sqrt[]{x}-4)dx=(2)/(3)\sqrt[]{x^3}-4x$

And if we evaluate between 16 and 9 we got:

$((2)/(3)\sqrt[]{16^3^{}}-4(16))-((2)/(3)\sqrt[]{9^3}-4(9))=(128)/(3)-64-18-36=(74)/(3)-28=-(10)/(3)$

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