we have
81, 27 9,....
a geometric sequence
so
a1=81
a2=27
a3=9
a3/a2=9/27=1/3
a2/a1=27/81=1/3
therefore
the common ratio r=1/3
Find out a4
a4=a3*r
a4=9*(1/3)=3
Find out a5
a5=a4*r
a5=3*(1/3)=1
Find out a6
a6=a5*r
a6=1*1/3=1/3
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