Question

A circle has a center at (-4,-5) and a radius of √6. what is the equation of the circle

Answer 1

Given:

a.) Circle's center: -4,-5

b.) Its radius is √6.

Recall: Standard equation of a circle.

`\text{ (x - h)}^2+(y-k)^2\text{ = }r^2`

Where,

(h,k) = the center of the circle

r = radius

Plugging in the given coordinates and radius of the circle, we get:

`\text{ (x - h)}^2+(y-k)^2\text{ = }r^2`
`\text{ \lbrack{}x - (-4)\rbrack}^2+\lbrack y-(-5)\rbrack^2\text{ = (}\sqrt[]{6})^2`