Question

Enter the values needed to find thelength CB. (Simplify your answer.)A(-3a, b)FB(3a, b)CB = V(4a)2 + ([?])C(-a, -5b)Distance Formula: d = V(x2 – xı)2 + (y2 – yı)2

Answer 1

The coordinates of point C is (-a,-5b) and point B is (3a,b).

Determine the distance between point C and B by using distance formula.

`\begin{gathered} CB=\sqrt[]{(-a-3a)^2+(-5b-b)^2} \\ =\sqrt[]{(-4a)^2+(-6b)^2} \\ =\sqrt[]{16a^2+36b^2} \end{gathered}`

So distance between point C and B is,

`\sqrt[]{16a^2+36b^2}`