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If a has a pressure of 25 atm a tem of 35 k and a volume of 26 but the themp changes to 67k and the volume changes to 89 liters what is the new pressure ?

If a has a pressure of 25 atm a tem of 35 k and a volume of 26 but the themp changes-example-1
User Scones
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For this question, we can use the Combined Gas Law, which is the law and formula that perfectly correlates all 3 (volume, temperature and pressure), the formula is:

P1V1/T1 = P2V2/T2

We have:

P1 = 25 atm

V1 = 26 L

T1 = 35 K

P2 = ?

V2 = 80 L

T2 = 67 K

Now we add these values into the formula:

25 * 26/35 = P2 * 80/67

18.57 = P2*80/67

80P2 = 1244.2

P2 = 15.55 atm is the new pressure

User Albeis
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