Answer:
136 m
Step-by-step explanation:
The diagram illustrating this problem is attached below:
Using trigonometric ratio:
![\tan 32\degree=(85)/(x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/lt8etcenl4y34m9myen0y8d7kk8s3s4b16.png)
We solve for x, the distance between the hiker and the cliff's base.
![\begin{gathered} x\tan 32\degree=85 \\ (x\tan 32\degree)/(\tan 32\degree)=(85)/(\tan 32\degree) \\ x=136.03m \\ x\approx136m \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/r7d8bnm3gmnekc6b1hzgdqgx9awtv9psgb.png)
To the nearest meter, the distance between the hiker and the cliff's base is 136m.