Given:
There are four cards numbered as
![3,\text{ }4,\text{ }5,\text{ and }6.](https://img.qammunity.org/2023/formulas/mathematics/college/wnrfvy8kvyfymnem0mxeqhmb8rjvu6imv5.png)
Required:
We have to find the probability of picking a 6 and then picking a 3.
Step-by-step explanation:
When you pick a card at random there are four possibilities.
The possibility of picking a 6 is only one.
Hence the probability of picking a 6 on the first card is
![(1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/nvzx4jpqhp8fdgb8f5vgtifqq8ndmxgctx.png)
Since you have put back the first card so in the second card there are again four possibilities.
The possibility of picking a 3 is only one.
Hence the probability of picking a 3 on the second card is
![(1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/nvzx4jpqhp8fdgb8f5vgtifqq8ndmxgctx.png)
Hence the probability of picking a 6 and then picking a 3 is
![(1)/(4)*(1)/(4)=(1)/(16)](https://img.qammunity.org/2023/formulas/mathematics/college/psfo6rzn6julp4kjvlhx2j7e5tfheh6sw8.png)
Final answer:
Hence the final answer is
![(1)/(16)](https://img.qammunity.org/2023/formulas/mathematics/high-school/5vmf8rvpgc3awy4da2yynht67mlrd0i9kk.png)