Question

A launcher shoots a tennis ball straight up into the air. What initial velocity must the ball be given so that it rises to a height of 45 meters?

Answer 1

Answer:

The initial velocity of the ball = 29.7 m/s

Explanations:

The height, H = 45 meters

The acceleration due to gravity, g = -9.8 m/s² (Since the ball is thrown up)

At maximum height, the velocity is 0 m/s. That is, v = 0m/s

We can get the initial velocity using the equation of motion below:

v² = u² + 2gH

0² = u² + 2(-9.8)(45)

0 = u² - 882

u² = 882

u = √882

u = 29.7 m/s

The initial velocity = 29.7 m/s