Question

In kite PQRS, m_OPO = 50° and m_ORO = 70°. Find m2PSR

Answer 1

m<PSR = 60°

Explanation:

Given:

m<OPQ = 50°

m<ORQ = 70°

Required:

m<PSR

Solution:

m<PQR + m<OPQ + m<ORQ = 180° (Sum of triangle)

m<PQR + 50 + 70 = 180 (Substitution)

m<PQR + 120 = 180

m<PQR = 180 - 120

m<PQR = 60°

One of the properties of a kite states that the angles where the unequal sides meets are congruent to each other. Therefore:

m<PSR = m<PQR

m<PSR = 60° (substitution)