Question

A 35% sucrose solution lost 240 mL by evaporation. After evaporation what is the sucrose concentration in the remaining 300 mL? Round your final answer to 2 decimal places if necessary.

Answer 1

`63.89\text{ \%}`

Step-by-step explanation:

Here, we want to get the sucrose concentration in the remaining 300 mL

From the question:

What is left after evaporation and what has left means the initial volume was 240 mL + 300 mL = 540 mL

Now from this total of 540 mL, 35% is sucrose, which means 65% is water

After evaporation, 300 mL is left

Let us calculate the percentage of water lost

We have that as:

`(240)/(540)*100\text{ = 44.44\% }`

Now, let us get the quantity/amount of water lost

Out of the total 100% water, 44.44% was lost

if 100% translates to 65%

44.44% will translate to x%

Thus, we have that as:

`x\text{ = }(44.44*65)/(100)\text{ = 28.89\%}`

What this simply means is that 28.89% of water was lost from the total 65%

The amount of water left is (65% - 28.89 %) = 36.11 %

The amount of sucrose left is thus:

`100-36.11\text{ = 63.89\%}`