Question

PLEASE HELP I HAVE FINALSSS​

Answer 1

Answer: 26.67 m/s

Step-by-step explanation:

Given

Length traveled by the ball
`s=40\ m`

Time taken to reach the goal post is
`t=3\ s`

Initial velocity
`u=0\ m/s`

Using the second equation of motion

`\Rightarrow s=ut+(1)/(2)at^2\\\Rightarrow 40=0+(1)/(2)a(3)^2\\\Rightarrow a=(80)/(9)\ m/s^2\\`

Now using

`\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2* (80)/(9)* 40\\\\\Rightarrow v=\sqrt{(80* 80)/(9)}=(80)/(3)\\\Rightarrow v=26.67\ m/s`

The velocity of ball will be 26.67 m/s