In order to determine the displacement of the vehicle, first calculate the acceleration, by using the following expression:
![a=(v_2-v_1)/(t_2-t_1)](https://img.qammunity.org/2023/formulas/physics/college/i7h58j8h6ivywsvn85qkxyxw57zdlg3xpn.png)
where t1, t2, v1 and v2 are values of time and velocity you can determine from the graph. For instance:
v1 = 0m/s
v2 =5m/s
t1 = 0s
t2 = 1s
By replacing the previous values of the parameters into the formula for a you get:
![a=(5(m)/(s)-0(m)/(s))/(1s-0s)=5(m)/(s^2)](https://img.qammunity.org/2023/formulas/physics/college/bkwpva1iusjbcqudlzv2fakvm3p4t4vn8i.png)
Now, to calculate the displacement, you can use the following expression:
![x=v_ot+(1)/(2)at^2](https://img.qammunity.org/2023/formulas/physics/college/xd0c0mte24btoe0ekrkowhgyxqalfwhkm9.png)
Between time t=0s and t=2s, you have vo = 0m/s.
Use a=5m/s^2 and t=2s and simplify into the expression for the displacement x:
![\begin{gathered} x=(0(m)/(s))(2s)+(1)/(2)(5(m)/(s^2))(2s)^2 \\ x=10m \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/p5fdn6tcafxbutbh4eqe1f2a9cpllobkcp.png)
Hence, the displacement of the vehicle in the given time interval is 10m