Question

I just need help cause if I don’t I don’t know what imma do

Answer 1

`P(32) = (1)/(90)`

`P(Odd) = (1)/(2)`

`P(Multiples\ 5) = (1)/(5)`

Explanation:

Given

Sample Space = 10 to 99

First, we calculate the sample size (n)

`n = 99 - 10 + 1`

`n = 90`

Solving (a): P(32)

In 10 to 99, there is only 1 32.

So,

`P(32) = (n(32))/(n)`

`P(32) = (1)/(90)`

Solving (b): P(Odd)

There are 45 odd numbers between 10 and 99

i.e.

`n(Odd) = 45`

So:

`P(Odd) = (n(Odd))/(n)`

`P(Odd) = (45)/(90)`

`P(Odd) = (1)/(2)`

Solving (c): P(Multiple of 5)

There are 18 multiples of 5 between 10 and 99

i.e

`P(Multiples\ 5) = (18)/(90)`

`P(Multiples\ 5) = (1)/(5)`