ANSWER:
6
Explanation:
Given:
When x = 16, y = 4
We know that it varies directly with the square root of x, so we can state the following:
![y=k\cdot\sqrt[]{x}](https://img.qammunity.org/2023/formulas/mathematics/college/8ad5gltzkcphx6cfk7h4385tpq1nk2jgw0.png)
We substitute and calculate k, just like this:
![\begin{gathered} 4=k\sqrt[]{16} \\ k=\frac{4}{\sqrt[]{16}} \\ k=(4)/(4)=1 \\ \text{ Therefore, the function is} \\ y=\sqrt[]{x} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pkxa5lpfxk9cwy8f4674tl4akdqyrh4cag.png)
Now, we calculate the value of y when x = 16 substituting in the function obtained, just like this:
![\begin{gathered} y=\sqrt[]{36} \\ y=6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rhlx2pmj1resklrnai4wts10owvw8izyzc.png)
The value of y is 6