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When lead(II) nitrate reacts with sodium iodide, what is the correct formula for the product lead(II) iodide?Pb 2Pb22Pol4Pb214Pb2Hoo.
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When lead(II) nitrate reacts with sodium iodide, what is the correct formula for the product lead(II) iodide?Pb 2Pb22Pol4Pb214Pb2Hoo.

When lead(II) nitrate reacts with sodium iodide, what is the correct formula for the-example-1
User PhearOfRayne
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1 Answer

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Lead (II) nitrate = Pb(NO3)2

Sodium iodide = NaI

When they react:

Pb(NO3)2 + 2NaI => 2NaNO3 + PbI2

PbI2 is formed as a product. It is called lead (II) iodide

Answer: PbI2

User Jack Chorley
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