1 Answer

Jake Griffin · Answer 1 · 2023-11-03T14:55:50+0000

Answer:

94.7925 square inches

The given figure is made up of a triangle and a semicircle. The area of the figure is expressed as:

$Area=area\text{ }of\text{ }triangle+area\text{ }of\text{ }semicircle$

Find the area of the triangle

Base = 14in

Height = 9in

$\begin{gathered} A_t=(1)/(2)* base* height \\ A_t=(1)/(2)*14*9 \\ A_t=7*9=63in^2 \end{gathered}$

Determine the area of the semicircle

Radius = 9in/2 = 4.5in

$\begin{gathered} A_s=(\pi r^2)/(2) \\ A_s=(3.14*4.5^2)/(2) \\ A_s=(63.585)/(2) \\ A_s=31.7925in^2 \end{gathered}$

Determine the area of the figure

$\begin{gathered} A=A_t+A_s \\ A=63+31.7925 \\ A=94.7925in^2 \end{gathered}$

Thereforethe area of the shape is 94.7925 square inches