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How many grams of Sulfur are there in 2.05 x 10^25 molecules of Calcium Sulfate?

User Curly
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1 Answer

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10 votes

Answer:

1090 grams Sulfur (3 sig-figs)

Step-by-step explanation:

Given 2.05 x 10²⁵ molecules CaSO₄ => 2.05 x 10²⁵ Sulfur atoms (subscript = 1 mole).

Converting 2.05 x 10²⁵ sulfur atoms to moles, divide by Avogadro's Number

(= 6.023 x 10²³ sulfur atoms / mole sulfur) => 2.05 x 10²⁵ sulfur atoms/6.023 x 10²³ sulfur atoms/mole sulfur atoms = 34.036 moles sulfur atoms.

Converting 34.036 moles sulfur to grams sulfur multiply by formula wt. of sulfur (=32g/mole S)

=> 34.036moles S x 32g/mole S = 1089.158 grams S ≅ 1090 g S (3 sig-figs)

User HSchmale
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