Question

A box is filled with 9 red crayons, 5 blue crayons, and 8 yellow crayons.A crayon is chosen at random from the box. Find the probability that it is a blue or a yellow crayon.Write your answer as a fraction

Answer 1

In a box, there are red, blue, and yellow crayons;

`\begin{gathered} n(r)=9 \\ n(b)=5 \\ n(y)=8 \\ n\mleft(T\mright)=22 \\ \\ \end{gathered}`
`P(\text{blue or yellow)= P(b) + P(y)}`
`\begin{gathered} \text{Probability (blue)=}\frac{number\text{ of blue}}{total\text{ crayon}} \\ \text{Probability (blue)=}(5)/(22) \end{gathered}`

Also;

`\begin{gathered} \text{Probability (yellow)=}\frac{number\text{ of yellow}}{total\text{ crayon}} \\ \text{Probability (yellow)=}(8)/(22) \end{gathered}`

Then;

`\begin{gathered} \text{Probability (blue or yellow)= }(5)/(22)+(8)/(22) \\ \text{Probability (blue or yellow)= }(13)/(22) \end{gathered}`