1 Answer

Scott Vander Molen · Answer 1 · 2023-09-11T18:25:10+0000

Step-by-step explanation:

The mole

Percent composition

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Data provided:

The molecular weight of C = 12.0107 g/mol

The molecular weight of C10H14 = 10 x 12.0107 + 14 x 1.00794 = 134.218 g/mol

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Procedure:

% by mass of C:

$\text{ \%by mass = }\frac{10\text{ x 12.0107 g/mol }}{134.218\text{ g/mol}}x100\text{ = 89.4865 \%}$

Answer: 89.4865 %

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