Question

Which of the following functions has a domain of I + -2 and 1 + 2?

Answer 1

We want to find the function which has a domain of x not equal to -2 and x not equal to 2

For this domain to exists, the function must not exist or be undefined at x = -2 and at x = 2

from the list of option given. Let us look for the option that is undefined at x = -2 and x = 2

Considering the third option

`\begin{gathered} y=(16)/(4-x^2) \\ set\text{ the denominator to zero to find the points of discontinuity} \\ 4-x^2=0 \\ 4=x^2 \\ x^2=4 \\ x=\pm2 \\ \text{The function }y=(16)/(4-x^2)\text{ exists at all points except x=-2 and x=2} \end{gathered}`

Therefore, the correct option is

`y=(16)/(4-x^2)`

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