Before adding the vectors, we will write them in ordered pair notation.
The first vector is represented by the ordered pair:
![(350,0).](https://img.qammunity.org/2023/formulas/mathematics/college/76bbw6kgbjdsaqhyvvpq2v0g2s4wf6njvr.png)
The second vector is represented by the ordered pair:
![(130cos60^(\circ),130sin60^(\circ)),](https://img.qammunity.org/2023/formulas/mathematics/college/wsqcjodu6lk8cyk353jrmuaa4j8e3wwtp1.png)
simplifying we get:
![(65,65√(3)).](https://img.qammunity.org/2023/formulas/mathematics/college/hb1lma899lra1dgy2su7txs4qaz03qo3mv.png)
Adding the vectors, we get:
![(350,0)+(65,65√(3))=(415,65√(3)).](https://img.qammunity.org/2023/formulas/mathematics/college/wkls98l854s6f70n20nbagaok30cqvfz1e.png)
Therefore, the magnitude of the resultant vector is:
![\sqrt{415^2+(65√(3))^2}.](https://img.qammunity.org/2023/formulas/mathematics/college/d90af1yjj6n0m31if16rj30pfto23qnimc.png)
Simplifying the above result, we get:
![\sqrt{415^2+(65√(3))^2}=430.](https://img.qammunity.org/2023/formulas/mathematics/college/uhrk3r3jpgg10qdgdfflonnrd2jeyqlpz4.png)
Answer:
![430.](https://img.qammunity.org/2023/formulas/mathematics/college/w3d16t5twizb0xe794la16j2mcqg6v3one.png)