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31 votes
31 votes
HELP PLEASE SHOW STEPS I HAVE NO IDEA WHAT TO DO. I HAVE BEEN TRYING TO FIGURE IT OUT BUT I CAN’T.

HELP PLEASE SHOW STEPS I HAVE NO IDEA WHAT TO DO. I HAVE BEEN TRYING TO FIGURE IT-example-1
User Mickl
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2 Answers

17 votes
17 votes


\text{Area of rectangle}=\text{lengh}*\text{width}\\\text{Area of square}=\text{side}^2

You just need to find differens between rectangle and square


\text{lengh}*\text{width}-\text{side}^2\\\\(x+10)(2x+5)-(x+1)^2=2x^2+5x+20x+50-x^2-2x-1=x^2+23x+49


x^2+23x+49\:\text{is our answer}

User Alexander Kurakin
by
3.2k points
25 votes
25 votes

Answer:
x^(2) +23x+49

Explanation:

To find the area of the shaded region, you must find the area of the larger rectangle [(x+10)×(2x+5)] and subtract the area of the smaller rectangle [(x+1)×(x+1)] from it.

First, you simplify the larger rectangle's area:

(x+10)×(2x+5) =
2x^(2) +25x+50

Then, simplify the smaller rectangle's area:

(x+1)×(x+1) =
x^(2) +2x+1

Finally, subtract the smaller rectangle's area from the larger rectangle's area:


(2x^(2) +25x+50) - (x^(2) +2x+1) = x^(2) +23x+49

Therefore, the final answer is
x^(2) +23x+49.

I hope this helps!

User Chef Mike
by
2.8k points