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A school bought $717 in basketball equipment and uniforms costing $38 each. The total cost was at most $2,769. Find the number of uniforms the school purchased.

User Otunba
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It is necessary to write the given situation in an algebraic way.

If x is the number of uniforms and each uniform costs $38, then, the cost of x uniforms is 38x. Moreover, the school payed $717 in basketball equipment.

The total cost was $2,769. You can write the previous situation as follow:

717 + 38x = 2769

solve the previous equation for x:

717 + 38x = 2,769 subtract 717 both sides

38x = 2,769 - 717

38x = 2,052 divide by 38 both sides

x = 2,052/38

x = 54

Hence, the number of uniforms the school bought was 54 uniforms

User Ipsit Gaur
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