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What is the specific heat of a 54.51 g piece of anunknown metal that exhibits a 45.2°C temperature changeupon absorbing 1870 J of heat?

User Polynomial
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1 Answer

3 votes

Answer:


0.76\text{ J/g.\degree C }

Step-by-step explanation:

Here, we want to calculate the specific heat capacity of an unknown piece of metal

Mathematically:


Q\text{ = mc}\Delta T

Where:

Q is the quantity of heat which is 1870 J

m is the mass of the piece which is 54.51 g

c is the specific heat capacity that we want to calculate

Delta T is the temperature change which is 45.2

Rewriting the equation in terms of c, we have it that:


c\text{ = }(Q)/(m\Delta T)

Substituting the values, we have it that:


c\text{ = }(1870)/(54.51*45.2)\text{ =0.76 J/g.\degree C }

User ComeIn
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