126k views
3 votes
A compound with a molecular mass of 302.7g has an empirical formula of Mg3N2.What is the molecular formula

A compound with a molecular mass of 302.7g has an empirical formula of Mg3N2.What-example-1

1 Answer

5 votes

10. Step 1 - Determine the mass of the empirical formula of Mg3N2.

Molar mass values: Mg = 24.3 g/mol and N = 14 g/mol

(3*24.3) + (2*14) = 100.9 g/mol

Step 2 - Calculate the molecular formula:

100.9 g ---- 1 mol

302.7 g ---- x mol

x = 3

This means that we need 3 minimum formulas to arrive at the molar mass of the compound. So, just multiply the element indices of the empirical formula by 3 to find the molecular formula, which is:

Mg9N6

Answer: Mg9N6

User CBrauer
by
4.7k points