Question

I need your immediate helpThe equation to the question is,y = (1/3) (x+2) - 1

Answer 1

The equation is given as,

`y=(1)/(3)(x+2)-1`

Simplify the expression a bit,

`\begin{gathered} y=(1)/(3)(x)+(1)/(3)(2)-1 \\ y=(1)/(3)(x)+(2-3)/(3) \\ y=(1)/(3)x-(1)/(3) \end{gathered}`

The function is a linear polynomial function.

Consider that the range of a polynomial function is the set of real numbers.

So it can be concluded that the range of the given function is the set of all real numbers. The corresponding interval for the range of the function is given by,

`(-\infty,\infty)`

Therefore, third option is the correct choice.