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4 ptsSuppose that $2060 is deposited into an account where the interest is compounded annually. This situationcan be modeled by the function.P (t) = 2060(1.018)where P(t) represent the value (in dollars) of the account at t years afterdepositing the $2060.In how many years will the money in the account double? {your final answer just number without decimal)

1 Answer

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Initial amount=$2060

Function:


P(t)=2060*(1.018)^t

Where p(t) is the final value. In this case p(t)=2060*2.


\begin{gathered} 2060*2=2060(1.018)^t \\ \end{gathered}

Solving for t:


\begin{gathered} (2060)/(2060)*2=1.018^t \\ 2=1.018^t \\ Log_(1.018)(2)=t \\ t=38.85\approx39 \end{gathered}

Answer: The years to double the money are 39.

User Henrique Barcelos
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