Question

What are the approximate zeros of f(x) = -x^2 - 3x + 6?

Answer 1

Given:

f(x) = -x^2 - 3x + 6?

Required:

f(x) = -x^2 - 3x + 6?

Step-by-step explanation:

`\begin{gathered} f(x)=-x^2-3x+6=0 \\ make\text{ the leading coefficient positive} \\ x^2+3x-6=0 \\ identifying\text{ the coefficients} \end{gathered}`

a=1,b=3,c=-6

`substitute\text{ into x=}(-b\pm√(b^2-4ac))/(2a)`

we get

`\begin{gathered} x=(-3\pm√(3^2-4*(-6)))/(2) \\ \\ x=(-3+√(33))/(2)\text{ or x =}(-3+√(33))/(2) \end{gathered}`

Required answer:

`x=(\pm3+√(33))/(2)`