SOLUTION
From the question, the r is increasing at the rate of 6.4 feet per seconds.
This means that the equation of the radius is
![r=6.4* t](https://img.qammunity.org/2023/formulas/mathematics/high-school/dynqoxmolv5ntagpdwzgvbn6i53aijqhq1.png)
So the function for the radius, in terms of t becomes
![r(t)=6.4t](https://img.qammunity.org/2023/formulas/mathematics/high-school/4ocn44bl2qe9vtrtyoojli3r53aittx4oa.png)
The Area A is given as
![A=\pi r^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/lcgfavc89jro4qntamn2b9gfliomu1jwuf.png)
So, the function for the area in terms of r becomes
![A(r)=\pi r^2](https://img.qammunity.org/2023/formulas/mathematics/college/6pueppmtyt8ob594uw2wh6d844gkkg074v.png)
Now, (A . r)t becomes
![\begin{gathered} (A.r)t=\pi r^2,\text{ where r\lparen t\rparen = 6.4t, we have } \\ (A.r)t=\pi*(6.4t)^2 \\ =40.96\pi t^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/cnwhd2togiranwpdavx8ooayob37pyio7u.png)
Hence the answer is
![(A.r)t=40.96\pi t^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/jx4h6o5xl16uiph48g5i2ofzp4gkig25c3.png)
The 3rd option is the answer