The profit yielded by a certain type of beverage is given by the difference between the gain in sales and the cost of those sales. For example, the total profits yielded by the liquor during the current week are given by:
![3201-884=2317](https://img.qammunity.org/2023/formulas/mathematics/college/2bd3q990ewcia6a5z7xbsc404p3facgsab.png)
So the profits this week were $2317. Then we do the same for last week:
![3176-898=2278](https://img.qammunity.org/2023/formulas/mathematics/college/brv5qnzz8kw6768xzgan6ia960vcozxd3m.png)
So the profits yielded by the liquor during both weeks are:
![2317+2278=4595](https://img.qammunity.org/2023/formulas/mathematics/college/o9t8wlwpi48r7787bqn8x9zpx8saljhhlm.png)
Now we do the same calculations for the rest of the beverages. For the beer we have during last week we have:
![1699-722=977](https://img.qammunity.org/2023/formulas/mathematics/college/um30ccq5ci28h1k9y457cn7dg1av3z7zo8.png)
So the profits were 977. For the current week we have:
![1803-728=1075](https://img.qammunity.org/2023/formulas/mathematics/college/bwpbvjiy0ah8ygyhw2cbzkekie7k6pqtdy.png)
So the total profits yielded by the beer are:
![1075+977=2052](https://img.qammunity.org/2023/formulas/mathematics/college/fpuvovompxhc3a67a7blcf1zukcvxvtb0x.png)
Then for the wine during last week we have:
![2992-1268=1724](https://img.qammunity.org/2023/formulas/mathematics/college/8tuzldc4do81ngr6ul17zly3rcoe506t9b.png)
And for the current week we have:
![2888-1243=1645](https://img.qammunity.org/2023/formulas/mathematics/college/y7modkvuto66ncts6g4251imx2okceqh5d.png)
Then the profits yielded by the wine are:
![1724+1645=3369](https://img.qammunity.org/2023/formulas/mathematics/college/slkvgxvz623c8oky05q9vw6yshd57nakk7.png)
In summary, the profits yielded by liquor, beer and wine during both weeks are $4595, $2052 and $3369 respectively. Then the answer is the liquor.