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The balanced chemical reaction done by Mr. Ken is given below2 Na + Cl2 = 2 NaClIf 5.8*10^24 molecules of chlorine gas was present in the flask, how many moles of chlorine gas was used

User Jeff Neet
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To convert the number of molecules to number of moles, we can use the relation between mole and the number of molecules:


1\text{ mole = 6}*10^(23)\text{ molecules}

In order to calculate the moles of chlorine gas (Cl2), we can use the following relation:


\begin{gathered} 1\text{ mole of Cl2 ------ 6}*10^(23)\text{ molecules of Cl2} \\ x\text{ moles of Cl2 ----- 5.8}*10^(24)\text{ molecules of Cl2} \\ \\ x=(5.8*10^(24))/(6*10^(23))=(5.8)/(6)*10^(24-23)=0.96*10=9.6\text{ moles} \end{gathered}

So, Mr. Ken has used 9.6 moles of Cl2.

User Meyerson
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