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Jiro Matchonson · Answer 1 · 2023-08-16T20:12:03+0000

The Solution:

The question assumed that the readings on the thermometer are normally distributed with mean 0 degrees and standard deviation 1.00 degrees.

$2.727\text{ \%=0.02727}$

So, from the z-table, we have that

$\begin{gathered} P(Z<0.02727)=-1.923 \\ P(Z>0.02727)=1.923 \end{gathered}$

So, for readings that too low, we have

$\begin{gathered} P(ZFor readings that too high, we have[tex]\begin{gathered} P(Z<1.923)\Rightarrow Z=(x-\mu)/(\sigma) \\ \\ 1.923=(x-0)/(1) \\ \\ 1.923=x \end{gathered}$

To draw a sketch that shows the two readings that are cutoff values of the rejected thermometer, we have

Assume that the readings on the thermometers are normally distributed with a mean-example-1

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