Question

I have three expression questions I need help solving for 1. x(25+2x-y)___________ -ZX= -3, Y= 4 Z= -1 2.2(x-3y)________ 6X= 6, Y= 1 3.(x^2+5)(x^2-x+2)-3X= -4

Answer 1

The first expression can be evaluated as follows:

`(x(25+2x-y))/(-z);x=-3,y=4,z=-1`

Substitute the given values to get:

`\begin{gathered} (x(25+2x-y))/(-z)=(-3(25+2(-3)-4))/(-(-1)) \\ =(-3(25-6-4))/(1) \\ =(-3(25-10))/(1) \\ =-3(15) \\ =-45 \end{gathered}`

The second expression can be evaluated as follows:

`(3x^2)(2(x-3y))/(6);x=6,y=1`

Substitute the given values to get:

`\begin{gathered} (3(6^2))(2(6-3(1)))/(6)=(2(3))/(6) \\ =(3*36)(6)/(6) \\ =108 \end{gathered}`

The third expression can be evaluated as follows:

`(x^2+5)(x^2-x+2)-3;x=-4`

Substitute the given value to get:

`\begin{gathered} \lbrack(-4)^2+5\rbrack\lbrack(-4)^2-(-4)+2\rbrack-3=(16+5)(16+4+2)-3 \\ =(21)(22)-3 \\ =462-3 \\ =459 \end{gathered}`