Lets find the equation of the line. The equation of the line that passes through a point is:

where x_0 and y_0 are the coordinates of the point and m is the slope.
Then, in this case m = 2 and the point (-1, 3)
We can write:

And solve for y:

The equation of the line is:

Now to see which of the options is a point in the line, we evaluate each x coordinate to see if give us the correct y coordinate.
The option a is (1, 4)

Option a cannot be.
Option b is (-3, 2)

Option b cannot be either
Option c is (1, 5) but we already know that the y coordinate when x = 1 is 7. C cannot be.
Finally, option D is (0, 5)

Wich is correct.
Thus, the correct answer is option D.