VARIABLES:
Let the variable "L" represent the number of hours Faith spends lifeguarding and "W" be the number of hours spent washing cars.
EQUATIONS:
Lifeguarding pays $13 per hour while washing cars pay $12 per hour.
The total amount Faith earned is $124. Therefore, we can have as an equation:

The total number of hours Faith worked is 10 hours. We can therefore write an equation to represent this to be:

SOLUTION:
The system of equations can be written to be:

To use the Elimination method, we can multiply Equation (2) by 12 to make the coefficients of W in the 2 equations be equal:

Subtract equation (3) from (1) to eliminate W:

We can find the value of W by substituting for L into equation (2):

ANSWERS:
