For questions a, the first step is to count the number of total possible routs.
The possible routs are:
The total number of routs is 6.
Now, there is only one rout that uses State and Fairview, so the probability of choosing the route is 1/6, as a percert it is 16.67%.
For the first part of question 6, we count the number of integers greater than 19 that have two digits. Those integers are 20,21,...,99. The total number of integers of this kind is 70.
You have 70 possible two digits numbers greater than 19.
Finally for the last part, we consider that the numbers for the pin cannot be repeated, then the first number can have 10 possible values, the second can have 9 possibles values and so on. So the possible choices for a 4-digit PIN without repeated numbers is 10*9*8*7=5040.