Question

14.02 i -27.14 j to polar form

Answer 1

the expression is:

`14.02i-27.14j`

So we can writte it like a coordinate:

`(14.02,27.14)`

Now we can transform that to polar form:

`\begin{gathered} r=\sqrt[]{x^2+y^2} \\ \tan (\theta)=(y)/(x) \end{gathered}`

So for r:

`\begin{gathered} r=\sqrt[]{14.02^2+27.14^2} \\ r=\sqrt[]{196.5+736.6} \\ r\approx\sqrt[]{933} \\ r=30.5 \end{gathered}`

and for theta

`\begin{gathered} \theta=\tan ^(-1)((27.14)/(14.02)) \\ \theta=\tan ^(-1)(1.9) \\ \theta=62.2º \end{gathered}`