Two lines are perpendicular if and only if their slopes fullfil:
![m_1m_2=-1](https://img.qammunity.org/2023/formulas/mathematics/college/g06uuiirl5abnt1q62hvbbgwyhsoapoxn1.png)
plugging the slope given we have:
![\begin{gathered} -(1)/(5)m_1=-1 \\ m_1=(-1)(-5) \\ m_1=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wgayq502dqgwodgd05n62a0vbvlu86zk5h.png)
this means that the line we are looking for has slope 5.
Now, the slope of a line is given by:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
we need to find two points that makes this slope equal to 5, choosing the points (1,4) and (2,9) we notice that:
![\begin{gathered} m=(9-4)/(2-1) \\ m=(5)/(1) \\ m=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ltgo1450yj8qxz1m7hw5lpvgf4arcysw9g.png)
Therefore the points we are looking for are (1,4) and (2,9)