Question

if you were to slowly add 0.3 M NaOH to 35 ml if 0.23M HCl how many ml of NaOH solution would be needed to reach the equivalence point??

Answer 1

M1V1 = M2V2

M1 = 0.23 M HCl

V1 = 35 mL

M2 = 0.3 M NaOH

V2 = ?

(0.23 M)(35 mL) = (0.3 M)V2 —> V2 = 27 mL NaOH