Let x be a random variable representing heart rates of individuals in a certain group. Given that the heart rates are normally distributed, we would calculate the z score by applying the formula for calculating z score which is expressed as
z = (x - μ)/σ
where
x is the sample mean
μ is the population mean
σ is the population standard deviation
From the information given,
μ = 70
σ = 3
x = 68
By substituting these values into the formula,
z = (68 - 70)/3 = 0.67
We want to find the probability that a randomly selected individual has a heart rate greater than 68 beats per minute. This is represented as
P(x > 68)
This can also be written as 1 - P(x ≤ 68)
We would find the probability value corresponding to a z score of 0.67 from the standard normal distribution table. It is
P(x ≤ 68) = 0.74857
Thus,
P(x > 68) = 1 - 0.74857 = 0.25143
Rounding to