Question

PLEASE HELP PHYSICS

Wiley coyote pushes a 5kg boulder from an initial height of 10m, the boulder rolls down the hill, across the road, and up the hill on the left. The rock is able to reach a height of 17 m before rolling back down. How fast did Wiley have to push the rock to make this happen?

Answer 1

v = 11.7 m / s

Step-by-step explanation:

For this exercise we can use the conservation of energy

starting point. Where you drop the stone

Em₀ = K + U = ½ m v² + m g h₁

final point. Point where the stone arrives

Em_f = U = mgh₂

We are assuming that there is no friction, so the energy is conserved

Em₀ = Em_f

½ m v² + m g h₁ = m g h₂

v² = 2g (h₂-h₁)

let's calculate

v² = 2 9.8 (17 - 10)

v = √137.2

v = 11.7 m / s