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Mike made 4 pints of hot chocolate for his friends if each of Mike's mugs holds 4/5 of a pint of liquid then how many friends will get hot chocolate?

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Given that each of Mike's mug holds


(4)/(5)\text{ of a pint of liquid}

This implies that


1\text{ mug holds }(4)/(5)\text{ pints}

Let x mugs in total, hold 4 pints of chocolate.

This implies that


x\text{ mugs hold 4 pints}

Since each friend is assigned a mug, the total number of mugs is the same as the total number of friends.

Thus,


\begin{gathered} 1\text{ mug }\Rightarrow(4)/(5)\text{ pints} \\ x\text{ mug }\Rightarrow4\text{ pints} \\ \end{gathered}

By cross-multiplication, we have


\begin{gathered} 1\text{ mug }*\text{ 4 pints = }(4)/(5)\text{ pints }*\text{ x mug} \\ \end{gathered}

Make x the subject of the formula


\begin{gathered} x=\frac{1\text{ mug }*\text{ 4 pints}}{(4)/(5)\text{ pints}} \\ x=\text{ 5} \end{gathered}

Thus, 5 friends will get hot chocolate

User Sheery
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