Question

if(-4x®y?) (62%y) = Ax"y"what are the values of A, m, and n?bA) A = 2, m = 6, n = 8B) A = -24, m = 6, n = 8C) A = 2, m = 9, n = 12D) A = -24, m = 9, n = 12d

Answer 1

We need to perform the product of:

`-4x^3y^2\text{ }\cdot(6x^3y^6)`

So we start by multiplying the numerical factors first:

(-4) times 6 = -24

This is then the value we enter for A = -24

Now for the product of the variables x:

one has the power "3" and the other one has the power 3 as well, so the new expression in power (exponent) form for x is x to the power "3+3 = 6"

`x^6`

Noe for the powers of the variable y:

we have to multiply y to the second power 92) times y to the sixth power (6), which leads to y to the "2 + 6 = 8" power, that is:

`y^8`

So now we write:

A = -24, m = 6 , and n = 8