The given function is:

Where D is the number of milligrams of drug remaining in the person after h hours of administering the drug.
It is required to find the number of milligrams that'll be present after 1 hour and 9 hours.
To do this, substitute h=1 and h=9, and find the value of D in each case.
Substitute h=1 into the function:

Hence, the number of milligrams present after 1 hour is about 2.58 mg.
Substitute h=9 into the function:

The number of milligrams present after 9 hours is about 0.08 mg.
Answers:
After 1 hour, there will be 2.58 mg.
After 9 hours there will be 0.08 mg.