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A car starts from rest and accelerates uniformly for a distance of 160 m over an 8.0-second time interval. The car's acceleration is---

1 Answer

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Given:

The initial velocity of the car is


v_i=0\text{ m/s}

The distance covered by the car is d = 160 m

The time duration is t = 8 s

Required: The car acceleration

Step-by-step explanation:

The acceleration can be calculated by the formula


d=v_it+(1)/(2)at^2

On substituting the values, the acceleration of the car will be


\begin{gathered} 160=0*8+(1)/(2)a*(8)^2 \\ 320=64a \\ a=5\text{ m/s}^2 \end{gathered}

Final Answer: The car's acceleration is 5 m/s^2.

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